Tuesday, September 18, 2007

Complicated variations

A. 1.d4 Nf6 2.c4 e6 3.Nf3 d5 4.Nc3 c6 5.Bg5 h6 6.Bh4 dxc4 7.e4 g5 8.Bg3 b5 9.Ne5 h5 10.h4 g4 11.Be2 Bb7 12.0-0 Nbd7 13.Qc2 Nxe5 14.Bxe5 Bg7 15.Rad1 0-0 16.Bg3 Nd7 17.f3


Aronian-Anand, Mexico City 2007 (Round 2)

17....c5!

B. In 2008 Vladimir Kramnik will play the winner of Mexico City unless he wins the event himself. Veselin Topalov as the loser of the last match in Elista will play the winner of the World Cup in Khanty Mansiysk which takes place at the end of the year. The winners of those matches will play for the title in 2009. However if Kramnik wins the WCCh tournament in Mexico City 2007, a match between Kramnik and Topalov, the current and the previous world champions, will take place in 2008. In that case, the winner of the Kramnik- Topalov match will play against the winner of the 2007 World Cup.

I think I can just about handle A - but could anybody explain B to me?

3 comments:

Tom Chivers said...

Nope.

Jonathan B said...

I'm hoping Anand wins so we can Anand - Kramnik next year. I think that will be a better match than Kramnik - Topalov II.

ejh said...

Kramnik's position tonight is the sort I love to play.